0.5 cal/(g·°C) = 2,092 J/(kg·K)
Also equals
How it works
J/(kg·K) = cal/(g·°C) × 4,184One calorie per gram-degree Celsius is exactly 4,184 joules per kilogram-kelvin, so multiplying by 4,184 turns calories per gram-degree Celsius into joules per kilogram-kelvin. For example, 0.385 cal/(g·°C) is 1,610.84 J/(kg·K).
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Multiply by 4,184
0.5 × 4,184 = 2,092 J/(kg·K) -
Nearby values
| Calories per gram-degree Celsius | Joules per kilogram-kelvin | Kilojoules per kilogram-kelvin | BTU per pound-degree Fahrenheit |
|---|---|---|---|
| 0.47 cal/(g·°C) | 1,966.48 J/(kg·K) | 1.97 | 0.47 |
| 0.48 cal/(g·°C) | 2,008.32 J/(kg·K) | 2.01 | 0.48 |
| 0.49 cal/(g·°C) | 2,050.16 J/(kg·K) | 2.05 | 0.49 |
| 0.5 cal/(g·°C) | 2,092 J/(kg·K) | 2.09 | 0.5 |
| 0.51 cal/(g·°C) | 2,133.84 J/(kg·K) | 2.13 | 0.51 |
| 0.52 cal/(g·°C) | 2,175.68 J/(kg·K) | 2.18 | 0.52 |
| 0.53 cal/(g·°C) | 2,217.52 J/(kg·K) | 2.22 | 0.53 |
Printed from rocketcalc.io/specific-heat/cal-per-g-c-to-j-per-kg-k/0.5