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Calories per gram-degree Celsius to joules per kilogram-kelvin

Convert calories per gram-degree Celsius to joules per kilogram-kelvin, with the math shown step by step.

Joules per kilogram-kelvin
2,092 J/(kg·K)

0.5 cal/(g·°C) = 2,092 J/(kg·K)

Also equals

How it works

J/(kg·K) = cal/(g·°C) × 4,184

One calorie per gram-degree Celsius is exactly 4,184 joules per kilogram-kelvin, so multiplying by 4,184 turns calories per gram-degree Celsius into joules per kilogram-kelvin. For example, 0.385 cal/(g·°C) is 1,610.84 J/(kg·K).

  1. Multiply by 4,184 0.5 × 4,184 = 2,092 J/(kg·K)

Nearby values

Calories per gram-degree Celsius Joules per kilogram-kelvin Kilojoules per kilogram-kelvin BTU per pound-degree Fahrenheit
0.47 cal/(g·°C) 1,966.48 J/(kg·K) 1.97 0.47
0.48 cal/(g·°C) 2,008.32 J/(kg·K) 2.01 0.48
0.49 cal/(g·°C) 2,050.16 J/(kg·K) 2.05 0.49
0.5 cal/(g·°C) 2,092 J/(kg·K) 2.09 0.5
0.51 cal/(g·°C) 2,133.84 J/(kg·K) 2.13 0.51
0.52 cal/(g·°C) 2,175.68 J/(kg·K) 2.18 0.52
0.53 cal/(g·°C) 2,217.52 J/(kg·K) 2.22 0.53