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Joules per kilogram-kelvin to calories per gram-degree Celsius

Convert joules per kilogram-kelvin to calories per gram-degree Celsius, with the math shown step by step.

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Calories per gram-degree Celsius
0.48 cal/(g·°C)

2,000 J/(kg·K) = 0.48 cal/(g·°C)

Also equals

How it works

cal/(g·°C) = J/(kg·K) ÷ 4,184

One calorie per gram-degree Celsius is exactly 4,184 joules per kilogram-kelvin, so dividing by 4,184 turns joules per kilogram-kelvin into calories per gram-degree Celsius. For example, 900 J/(kg·K) is about 0.2151 cal/(g·°C).

  1. Divide by 4,184 2,000 ÷ 4,184 = 0.48 cal/(g·°C)

Nearby values

Joules per kilogram-kelvin Calories per gram-degree Celsius BTU per pound-degree Fahrenheit Kilojoules per kilogram-kelvin
1,970 J/(kg·K) 0.47 cal/(g·°C) 0.47 1.97
1,980 J/(kg·K) 0.47 cal/(g·°C) 0.47 1.98
1,990 J/(kg·K) 0.48 cal/(g·°C) 0.48 1.99
2,000 J/(kg·K) 0.48 cal/(g·°C) 0.48 2
2,010 J/(kg·K) 0.48 cal/(g·°C) 0.48 2.01
2,020 J/(kg·K) 0.48 cal/(g·°C) 0.48 2.02
2,030 J/(kg·K) 0.49 cal/(g·°C) 0.48 2.03

Printed from rocketcalc.io/specific-heat/j-per-kg-k-to-cal-per-g-c/2000