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Joules per kilogram-kelvin to calories per gram-degree Celsius

Convert joules per kilogram-kelvin to calories per gram-degree Celsius, with the math shown step by step.

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Calories per gram-degree Celsius
0.49 cal/(g·°C)

2,032 J/(kg·K) = 0.49 cal/(g·°C)

Also equals

How it works

cal/(g·°C) = J/(kg·K) ÷ 4,184

One calorie per gram-degree Celsius is exactly 4,184 joules per kilogram-kelvin, so dividing by 4,184 turns joules per kilogram-kelvin into calories per gram-degree Celsius. For example, 900 J/(kg·K) is about 0.2151 cal/(g·°C).

  1. Divide by 4,184 2,032 ÷ 4,184 = 0.49 cal/(g·°C)

Nearby values

Joules per kilogram-kelvin Calories per gram-degree Celsius BTU per pound-degree Fahrenheit Kilojoules per kilogram-kelvin
2,002 J/(kg·K) 0.48 cal/(g·°C) 0.48 2
2,012 J/(kg·K) 0.48 cal/(g·°C) 0.48 2.01
2,022 J/(kg·K) 0.48 cal/(g·°C) 0.48 2.02
2,032 J/(kg·K) 0.49 cal/(g·°C) 0.49 2.03
2,042 J/(kg·K) 0.49 cal/(g·°C) 0.49 2.04
2,052 J/(kg·K) 0.49 cal/(g·°C) 0.49 2.05
2,062 J/(kg·K) 0.49 cal/(g·°C) 0.49 2.06

Printed from rocketcalc.io/specific-heat/j-per-kg-k-to-cal-per-g-c/2032