0.83 BTU/(h·ft·°F) = 1.44 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
0.83 ÷ 0.577789316543 = 1.44 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 0.53 BTU/(h·ft·°F) | 0.92 W/(m·K) | 0.79 | 6.36 |
| 0.63 BTU/(h·ft·°F) | 1.09 W/(m·K) | 0.94 | 7.56 |
| 0.73 BTU/(h·ft·°F) | 1.26 W/(m·K) | 1.09 | 8.76 |
| 0.83 BTU/(h·ft·°F) | 1.44 W/(m·K) | 1.24 | 9.96 |
| 0.93 BTU/(h·ft·°F) | 1.61 W/(m·K) | 1.38 | 11.16 |
| 1.03 BTU/(h·ft·°F) | 1.78 W/(m·K) | 1.53 | 12.36 |
| 1.13 BTU/(h·ft·°F) | 1.96 W/(m·K) | 1.68 | 13.56 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/0.83