1.18 BTU/(h·ft·°F) = 2.04 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
1.18 ÷ 0.577789316543 = 2.04 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 0.88 BTU/(h·ft·°F) | 1.52 W/(m·K) | 1.31 | 10.56 |
| 0.98 BTU/(h·ft·°F) | 1.7 W/(m·K) | 1.46 | 11.76 |
| 1.08 BTU/(h·ft·°F) | 1.87 W/(m·K) | 1.61 | 12.96 |
| 1.18 BTU/(h·ft·°F) | 2.04 W/(m·K) | 1.76 | 14.16 |
| 1.28 BTU/(h·ft·°F) | 2.22 W/(m·K) | 1.91 | 15.36 |
| 1.38 BTU/(h·ft·°F) | 2.39 W/(m·K) | 2.06 | 16.56 |
| 1.48 BTU/(h·ft·°F) | 2.56 W/(m·K) | 2.2 | 17.76 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/1.18