1.58 BTU/(h·ft·°F) = 2.73 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
1.58 ÷ 0.577789316543 = 2.73 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 1.28 BTU/(h·ft·°F) | 2.22 W/(m·K) | 1.91 | 15.36 |
| 1.38 BTU/(h·ft·°F) | 2.39 W/(m·K) | 2.06 | 16.56 |
| 1.48 BTU/(h·ft·°F) | 2.56 W/(m·K) | 2.2 | 17.76 |
| 1.58 BTU/(h·ft·°F) | 2.73 W/(m·K) | 2.35 | 18.96 |
| 1.68 BTU/(h·ft·°F) | 2.91 W/(m·K) | 2.5 | 20.16 |
| 1.78 BTU/(h·ft·°F) | 3.08 W/(m·K) | 2.65 | 21.36 |
| 1.88 BTU/(h·ft·°F) | 3.25 W/(m·K) | 2.8 | 22.56 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/1.58