20 BTU/(h·ft·°F) = 34.61 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
20 ÷ 0.577789316543 = 34.61 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 19.7 BTU/(h·ft·°F) | 34.1 W/(m·K) | 29.34 | 236.4 |
| 19.8 BTU/(h·ft·°F) | 34.27 W/(m·K) | 29.49 | 237.6 |
| 19.9 BTU/(h·ft·°F) | 34.44 W/(m·K) | 29.63 | 238.8 |
| 20 BTU/(h·ft·°F) | 34.61 W/(m·K) | 29.78 | 240 |
| 20.1 BTU/(h·ft·°F) | 34.79 W/(m·K) | 29.93 | 241.2 |
| 20.2 BTU/(h·ft·°F) | 34.96 W/(m·K) | 30.08 | 242.4 |
| 20.3 BTU/(h·ft·°F) | 35.13 W/(m·K) | 30.23 | 243.6 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/20