28.11 BTU/(h·ft·°F) = 48.65 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
28.11 ÷ 0.577789316543 = 48.65 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 27.81 BTU/(h·ft·°F) | 48.13 W/(m·K) | 41.41 | 333.72 |
| 27.91 BTU/(h·ft·°F) | 48.3 W/(m·K) | 41.56 | 334.92 |
| 28.01 BTU/(h·ft·°F) | 48.48 W/(m·K) | 41.71 | 336.12 |
| 28.11 BTU/(h·ft·°F) | 48.65 W/(m·K) | 41.86 | 337.32 |
| 28.21 BTU/(h·ft·°F) | 48.82 W/(m·K) | 42.01 | 338.52 |
| 28.31 BTU/(h·ft·°F) | 49 W/(m·K) | 42.16 | 339.72 |
| 28.41 BTU/(h·ft·°F) | 49.17 W/(m·K) | 42.31 | 340.92 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/28.11