29.06 BTU/(h·ft·°F) = 50.3 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
29.06 ÷ 0.577789316543 = 50.3 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 28.76 BTU/(h·ft·°F) | 49.78 W/(m·K) | 42.83 | 345.12 |
| 28.86 BTU/(h·ft·°F) | 49.95 W/(m·K) | 42.98 | 346.32 |
| 28.96 BTU/(h·ft·°F) | 50.12 W/(m·K) | 43.13 | 347.52 |
| 29.06 BTU/(h·ft·°F) | 50.3 W/(m·K) | 43.27 | 348.72 |
| 29.16 BTU/(h·ft·°F) | 50.47 W/(m·K) | 43.42 | 349.92 |
| 29.26 BTU/(h·ft·°F) | 50.64 W/(m·K) | 43.57 | 351.12 |
| 29.36 BTU/(h·ft·°F) | 50.81 W/(m·K) | 43.72 | 352.32 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/29.06