29.18 BTU/(h·ft·°F) = 50.5 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
29.18 ÷ 0.577789316543 = 50.5 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 28.88 BTU/(h·ft·°F) | 49.98 W/(m·K) | 43.01 | 346.56 |
| 28.98 BTU/(h·ft·°F) | 50.16 W/(m·K) | 43.16 | 347.76 |
| 29.08 BTU/(h·ft·°F) | 50.33 W/(m·K) | 43.3 | 348.96 |
| 29.18 BTU/(h·ft·°F) | 50.5 W/(m·K) | 43.45 | 350.16 |
| 29.28 BTU/(h·ft·°F) | 50.68 W/(m·K) | 43.6 | 351.36 |
| 29.38 BTU/(h·ft·°F) | 50.85 W/(m·K) | 43.75 | 352.56 |
| 29.48 BTU/(h·ft·°F) | 51.02 W/(m·K) | 43.9 | 353.76 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/29.18