29.24 BTU/(h·ft·°F) = 50.61 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
29.24 ÷ 0.577789316543 = 50.61 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 28.94 BTU/(h·ft·°F) | 50.09 W/(m·K) | 43.1 | 347.28 |
| 29.04 BTU/(h·ft·°F) | 50.26 W/(m·K) | 43.25 | 348.48 |
| 29.14 BTU/(h·ft·°F) | 50.43 W/(m·K) | 43.39 | 349.68 |
| 29.24 BTU/(h·ft·°F) | 50.61 W/(m·K) | 43.54 | 350.88 |
| 29.34 BTU/(h·ft·°F) | 50.78 W/(m·K) | 43.69 | 352.08 |
| 29.44 BTU/(h·ft·°F) | 50.95 W/(m·K) | 43.84 | 353.28 |
| 29.54 BTU/(h·ft·°F) | 51.13 W/(m·K) | 43.99 | 354.48 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/29.24