29.66 BTU/(h·ft·°F) = 51.33 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
29.66 ÷ 0.577789316543 = 51.33 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 29.36 BTU/(h·ft·°F) | 50.81 W/(m·K) | 43.72 | 352.32 |
| 29.46 BTU/(h·ft·°F) | 50.99 W/(m·K) | 43.87 | 353.52 |
| 29.56 BTU/(h·ft·°F) | 51.16 W/(m·K) | 44.02 | 354.72 |
| 29.66 BTU/(h·ft·°F) | 51.33 W/(m·K) | 44.17 | 355.92 |
| 29.76 BTU/(h·ft·°F) | 51.51 W/(m·K) | 44.32 | 357.12 |
| 29.86 BTU/(h·ft·°F) | 51.68 W/(m·K) | 44.47 | 358.32 |
| 29.96 BTU/(h·ft·°F) | 51.85 W/(m·K) | 44.62 | 359.52 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/29.66