29.78 BTU/(h·ft·°F) = 51.54 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
29.78 ÷ 0.577789316543 = 51.54 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 29.48 BTU/(h·ft·°F) | 51.02 W/(m·K) | 43.9 | 353.76 |
| 29.58 BTU/(h·ft·°F) | 51.2 W/(m·K) | 44.05 | 354.96 |
| 29.68 BTU/(h·ft·°F) | 51.37 W/(m·K) | 44.2 | 356.16 |
| 29.78 BTU/(h·ft·°F) | 51.54 W/(m·K) | 44.35 | 357.36 |
| 29.88 BTU/(h·ft·°F) | 51.71 W/(m·K) | 44.5 | 358.56 |
| 29.98 BTU/(h·ft·°F) | 51.89 W/(m·K) | 44.65 | 359.76 |
| 30.08 BTU/(h·ft·°F) | 52.06 W/(m·K) | 44.79 | 360.96 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/29.78