29.82 BTU/(h·ft·°F) = 51.61 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
29.82 ÷ 0.577789316543 = 51.61 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 29.52 BTU/(h·ft·°F) | 51.09 W/(m·K) | 43.96 | 354.24 |
| 29.62 BTU/(h·ft·°F) | 51.26 W/(m·K) | 44.11 | 355.44 |
| 29.72 BTU/(h·ft·°F) | 51.44 W/(m·K) | 44.26 | 356.64 |
| 29.82 BTU/(h·ft·°F) | 51.61 W/(m·K) | 44.41 | 357.84 |
| 29.92 BTU/(h·ft·°F) | 51.78 W/(m·K) | 44.56 | 359.04 |
| 30.02 BTU/(h·ft·°F) | 51.96 W/(m·K) | 44.7 | 360.24 |
| 30.12 BTU/(h·ft·°F) | 52.13 W/(m·K) | 44.85 | 361.44 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/29.82