29.89 BTU/(h·ft·°F) = 51.73 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
29.89 ÷ 0.577789316543 = 51.73 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 29.59 BTU/(h·ft·°F) | 51.21 W/(m·K) | 44.06 | 355.08 |
| 29.69 BTU/(h·ft·°F) | 51.39 W/(m·K) | 44.21 | 356.28 |
| 29.79 BTU/(h·ft·°F) | 51.56 W/(m·K) | 44.36 | 357.48 |
| 29.89 BTU/(h·ft·°F) | 51.73 W/(m·K) | 44.51 | 358.68 |
| 29.99 BTU/(h·ft·°F) | 51.9 W/(m·K) | 44.66 | 359.88 |
| 30.09 BTU/(h·ft·°F) | 52.08 W/(m·K) | 44.81 | 361.08 |
| 30.19 BTU/(h·ft·°F) | 52.25 W/(m·K) | 44.96 | 362.28 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/29.89