30.07 BTU/(h·ft·°F) = 52.04 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
30.07 ÷ 0.577789316543 = 52.04 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 29.77 BTU/(h·ft·°F) | 51.52 W/(m·K) | 44.33 | 357.24 |
| 29.87 BTU/(h·ft·°F) | 51.7 W/(m·K) | 44.48 | 358.44 |
| 29.97 BTU/(h·ft·°F) | 51.87 W/(m·K) | 44.63 | 359.64 |
| 30.07 BTU/(h·ft·°F) | 52.04 W/(m·K) | 44.78 | 360.84 |
| 30.17 BTU/(h·ft·°F) | 52.22 W/(m·K) | 44.93 | 362.04 |
| 30.27 BTU/(h·ft·°F) | 52.39 W/(m·K) | 45.08 | 363.24 |
| 30.37 BTU/(h·ft·°F) | 52.56 W/(m·K) | 45.23 | 364.44 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/30.07