30.13 BTU/(h·ft·°F) = 52.15 W/(m·K)
Also equals
How it works
W/(m·K) = BTU/(h·ft·°F) ÷ 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so dividing by 0.577789316543 turns BTU per hour-foot-degree Fahrenheit into watts per meter-kelvin. For example, 1 BTU/(h·ft·°F) is about 1.731 W/(m·K).
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Divide by 0.577789316543
30.13 ÷ 0.577789316543 = 52.15 W/(m·K) -
Nearby values
| BTU per hour-foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 29.83 BTU/(h·ft·°F) | 51.63 W/(m·K) | 44.42 | 357.96 |
| 29.93 BTU/(h·ft·°F) | 51.8 W/(m·K) | 44.57 | 359.16 |
| 30.03 BTU/(h·ft·°F) | 51.97 W/(m·K) | 44.72 | 360.36 |
| 30.13 BTU/(h·ft·°F) | 52.15 W/(m·K) | 44.87 | 361.56 |
| 30.23 BTU/(h·ft·°F) | 52.32 W/(m·K) | 45.02 | 362.76 |
| 30.33 BTU/(h·ft·°F) | 52.49 W/(m·K) | 45.17 | 363.96 |
| 30.43 BTU/(h·ft·°F) | 52.67 W/(m·K) | 45.32 | 365.16 |
Printed from rocketcalc.io/thermal-conductivity/btu-per-h-ft-f-to-w-per-mk/30.13