5 BTU·in/(h·ft²·°F) = 0.72 W/(m·K)
Also equals
How it works
W/(m·K) = BTU·in/(h·ft²·°F) ÷ 6.9334718One watt per meter-kelvin is about 6.9334718 BTU-inch per hour-square foot-degree Fahrenheit, so dividing by 6.9334718 turns BTU-inch per hour-square foot-degree Fahrenheit into watts per meter-kelvin. For example, 0.27 BTU·in/(h·ft²·°F) is about 0.03894 W/(m·K).
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Divide by 6.9334718
5 ÷ 6.9334718 = 0.72 W/(m·K) -
Nearby values
| BTU-inch per hour-square foot-degree Fahrenheit | Watts per meter-kelvin | Kilocalories per hour-meter-degree Celsius | BTU per hour-foot-degree Fahrenheit |
|---|---|---|---|
| 4.97 BTU·in/(h·ft²·°F) | 0.72 W/(m·K) | 0.62 | 0.41 |
| 4.98 BTU·in/(h·ft²·°F) | 0.72 W/(m·K) | 0.62 | 0.42 |
| 4.99 BTU·in/(h·ft²·°F) | 0.72 W/(m·K) | 0.62 | 0.42 |
| 5 BTU·in/(h·ft²·°F) | 0.72 W/(m·K) | 0.62 | 0.42 |
| 5.01 BTU·in/(h·ft²·°F) | 0.72 W/(m·K) | 0.62 | 0.42 |
| 5.02 BTU·in/(h·ft²·°F) | 0.72 W/(m·K) | 0.62 | 0.42 |
| 5.03 BTU·in/(h·ft²·°F) | 0.73 W/(m·K) | 0.62 | 0.42 |
Printed from rocketcalc.io/thermal-conductivity/k-value-to-w-per-mk/5