0.6 W/(m·K) = 0.35 BTU/(h·ft·°F)
Also equals
How it works
BTU/(h·ft·°F) = W/(m·K) × 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so multiplying by 0.577789316543 turns watts per meter-kelvin into BTU per hour-foot-degree Fahrenheit. For example, 1 W/(m·K) is about 0.5778 BTU/(h·ft·°F).
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Multiply by 0.577789316543
0.6 × 0.577789316543 = 0.35 BTU/(h·ft·°F) -
Nearby values
| Watts per meter-kelvin | BTU per hour-foot-degree Fahrenheit | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 0.3 W/(m·K) | 0.17 BTU/(h·ft·°F) | 0.26 | 2.08 |
| 0.4 W/(m·K) | 0.23 BTU/(h·ft·°F) | 0.34 | 2.77 |
| 0.5 W/(m·K) | 0.29 BTU/(h·ft·°F) | 0.43 | 3.47 |
| 0.6 W/(m·K) | 0.35 BTU/(h·ft·°F) | 0.52 | 4.16 |
| 0.7 W/(m·K) | 0.4 BTU/(h·ft·°F) | 0.6 | 4.85 |
| 0.8 W/(m·K) | 0.46 BTU/(h·ft·°F) | 0.69 | 5.55 |
| 0.9 W/(m·K) | 0.52 BTU/(h·ft·°F) | 0.77 | 6.24 |
Printed from rocketcalc.io/thermal-conductivity/w-per-mk-to-btu-per-h-ft-f/0.6