1.53 W/(m·K) = 0.88 BTU/(h·ft·°F)
Also equals
How it works
BTU/(h·ft·°F) = W/(m·K) × 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so multiplying by 0.577789316543 turns watts per meter-kelvin into BTU per hour-foot-degree Fahrenheit. For example, 1 W/(m·K) is about 0.5778 BTU/(h·ft·°F).
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Multiply by 0.577789316543
1.53 × 0.577789316543 = 0.88 BTU/(h·ft·°F) -
Nearby values
| Watts per meter-kelvin | BTU per hour-foot-degree Fahrenheit | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 1.23 W/(m·K) | 0.71 BTU/(h·ft·°F) | 1.06 | 8.53 |
| 1.33 W/(m·K) | 0.77 BTU/(h·ft·°F) | 1.14 | 9.22 |
| 1.43 W/(m·K) | 0.83 BTU/(h·ft·°F) | 1.23 | 9.91 |
| 1.53 W/(m·K) | 0.88 BTU/(h·ft·°F) | 1.32 | 10.61 |
| 1.63 W/(m·K) | 0.94 BTU/(h·ft·°F) | 1.4 | 11.3 |
| 1.73 W/(m·K) | 1 BTU/(h·ft·°F) | 1.49 | 11.99 |
| 1.83 W/(m·K) | 1.06 BTU/(h·ft·°F) | 1.57 | 12.69 |
Printed from rocketcalc.io/thermal-conductivity/w-per-mk-to-btu-per-h-ft-f/1.53