2.39 W/(m·K) = 1.38 BTU/(h·ft·°F)
Also equals
How it works
BTU/(h·ft·°F) = W/(m·K) × 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so multiplying by 0.577789316543 turns watts per meter-kelvin into BTU per hour-foot-degree Fahrenheit. For example, 1 W/(m·K) is about 0.5778 BTU/(h·ft·°F).
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Multiply by 0.577789316543
2.39 × 0.577789316543 = 1.38 BTU/(h·ft·°F) -
Nearby values
| Watts per meter-kelvin | BTU per hour-foot-degree Fahrenheit | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 2.09 W/(m·K) | 1.21 BTU/(h·ft·°F) | 1.8 | 14.49 |
| 2.19 W/(m·K) | 1.27 BTU/(h·ft·°F) | 1.88 | 15.18 |
| 2.29 W/(m·K) | 1.32 BTU/(h·ft·°F) | 1.97 | 15.88 |
| 2.39 W/(m·K) | 1.38 BTU/(h·ft·°F) | 2.06 | 16.57 |
| 2.49 W/(m·K) | 1.44 BTU/(h·ft·°F) | 2.14 | 17.26 |
| 2.59 W/(m·K) | 1.5 BTU/(h·ft·°F) | 2.23 | 17.96 |
| 2.69 W/(m·K) | 1.55 BTU/(h·ft·°F) | 2.31 | 18.65 |
Printed from rocketcalc.io/thermal-conductivity/w-per-mk-to-btu-per-h-ft-f/2.39