2.85 W/(m·K) = 1.65 BTU/(h·ft·°F)
Also equals
How it works
BTU/(h·ft·°F) = W/(m·K) × 0.577789316543One watt per meter-kelvin is exactly 0.577789316543 BTU per hour-foot-degree Fahrenheit, so multiplying by 0.577789316543 turns watts per meter-kelvin into BTU per hour-foot-degree Fahrenheit. For example, 1 W/(m·K) is about 0.5778 BTU/(h·ft·°F).
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Multiply by 0.577789316543
2.85 × 0.577789316543 = 1.65 BTU/(h·ft·°F) -
Nearby values
| Watts per meter-kelvin | BTU per hour-foot-degree Fahrenheit | Kilocalories per hour-meter-degree Celsius | BTU-inch per hour-square foot-degree Fahrenheit |
|---|---|---|---|
| 2.55 W/(m·K) | 1.47 BTU/(h·ft·°F) | 2.19 | 17.68 |
| 2.65 W/(m·K) | 1.53 BTU/(h·ft·°F) | 2.28 | 18.37 |
| 2.75 W/(m·K) | 1.59 BTU/(h·ft·°F) | 2.37 | 19.07 |
| 2.85 W/(m·K) | 1.65 BTU/(h·ft·°F) | 2.45 | 19.76 |
| 2.95 W/(m·K) | 1.7 BTU/(h·ft·°F) | 2.54 | 20.45 |
| 3.05 W/(m·K) | 1.76 BTU/(h·ft·°F) | 2.62 | 21.15 |
| 3.15 W/(m·K) | 1.82 BTU/(h·ft·°F) | 2.71 | 21.84 |
Printed from rocketcalc.io/thermal-conductivity/w-per-mk-to-btu-per-h-ft-f/2.85