0.5 W/(m·K) = 3.47 BTU·in/(h·ft²·°F)
Also equals
How it works
BTU·in/(h·ft²·°F) = W/(m·K) × 6.9334718One watt per meter-kelvin is about 6.9334718 BTU-inch per hour-square foot-degree Fahrenheit, so multiplying by 6.9334718 turns watts per meter-kelvin into BTU-inch per hour-square foot-degree Fahrenheit. For example, 0.04 W/(m·K) is about 0.2773 BTU·in/(h·ft²·°F).
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Multiply by 6.9334718
0.5 × 6.9334718 = 3.47 BTU·in/(h·ft²·°F) -
Nearby values
| Watts per meter-kelvin | BTU-inch per hour-square foot-degree Fahrenheit | Kilocalories per hour-meter-degree Celsius | BTU per hour-foot-degree Fahrenheit |
|---|---|---|---|
| 0.497 W/(m·K) | 3.45 BTU·in/(h·ft²·°F) | 0.43 | 0.29 |
| 0.498 W/(m·K) | 3.45 BTU·in/(h·ft²·°F) | 0.43 | 0.29 |
| 0.499 W/(m·K) | 3.46 BTU·in/(h·ft²·°F) | 0.43 | 0.29 |
| 0.5 W/(m·K) | 3.47 BTU·in/(h·ft²·°F) | 0.43 | 0.29 |
| 0.501 W/(m·K) | 3.47 BTU·in/(h·ft²·°F) | 0.43 | 0.29 |
| 0.502 W/(m·K) | 3.48 BTU·in/(h·ft²·°F) | 0.43 | 0.29 |
| 0.503 W/(m·K) | 3.49 BTU·in/(h·ft²·°F) | 0.43 | 0.29 |
Printed from rocketcalc.io/thermal-conductivity/w-per-mk-to-k-value/0.5