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Orbital speed
How it works
v = √(G M ÷ r) · T = 2π r ÷ vIn a circular orbit the satellite falls toward the planet exactly as fast as the surface curves away beneath it. The needed speed is √(GM ÷ r), which is escape velocity divided by √2. The International Space Station, about 420 km up, goes around 7.66 km/s and laps Earth every 93 minutes; higher orbits are slower and take longer.
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Distance from the center
6,371,000 m + 420,000 m = 6,791,000 m -
√(G M ÷ r)
√(6.6743 × 10⁻¹¹ × 5.9722 × 10²⁴ kg ÷ 6,791,000 m) = 7,661.312 m/s -
Circumference ÷ speed
2π × 6,791,000 ÷ 7,661.312 = 1:32:49 -
Printed from rocketcalc.io/physics/orbital-velocity